by cliff1066™

Question by Derrick: Can someone please solve this math riddle?
A old man, owning many houses and hotels, finding himself well advanced in years, called his boys together and told them that he wished to divide his property, between them while he was still alive. “Listen Glen,” he said to the eldest, “you may take as many houses as you think you could take care of, and your wife Nancy may have one ninth of all the houses left.”

Calling the second son he said, “Henry, you may take the same number of houses that Glen took, plus one extra house because Glen had the first pick. To your good wife, Sally, I will give one ninth of what will be left.”

To the third son he made a similar statement. He was to take one house more than the second son, and his wife was to have one ninth of those left. The same applied to the other sons. Each took one house more than his next oldest brother, and each son’s wife took one ninth of the remainder.

After the youngest son had taken his houses, there were none left for his wife. Then the old man said: “Since hotels are worth twice as much as houses, we will divide up my seven hotels so that each family will own property of equal value.”

The problem is to tell how many houses the old man owned and how many sons he had.

Best answer:

Answer by kakumei_keahi
I like mine more.

A infinite number of mathematicians walk into a bar.
The first says “I’d like a beer”
the second says “I’d like half a beer”
the third says “I’d like a quarter of a beer”

The bartender looks at them then says “You’re all stupid” then pours them two beers.

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